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How do you solve for y in #x-2y=1 #?

Answer 1

Isaiah Anthony

#color(green)(y =( x- 1)/2 #

#x-color(blue)(2y)=1#

Since we need to solve for #y# we need to isolate the term containing #y#:

#x- 1 = color(blue)(2y)#

#color(green)(2)y = x- 1 #

#y = (x- 1)/color(green)(2) #

#y =( x- 1)/2 #

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Answer 2

Jace Anderson

To solve for ( y ) in ( x - 2y = 1 ), you need to isolate ( y ) on one side of the equation. Here's the step-by-step process:

Start with the equation: ( x - 2y = 1 ).
Subtract ( x ) from both sides to move the term involving ( y ) to one side: ( -2y = 1 - x ).
Divide both sides by ( -2 ) to solve for ( y ): ( y = \frac{1 - x}{2} ).

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Answer 3

Abigail Allen

To solve for y in the equation x - 2y = 1, you would first isolate the term with y on one side of the equation.

Step 1: Move the x term to the other side by adding 2y to both sides of the equation: x - 2y + 2y = 1 + 2y x = 1 + 2y

Step 2: Move the constant term to the other side by subtracting 1 from both sides of the equation: x - 1 = 1 + 2y - 1 x - 1 = 2y

Step 3: Divide both sides by 2 to solve for y: (x - 1) / 2 = (2y) / 2 (x - 1) / 2 = y

Therefore, y = (x - 1) / 2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.