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How do you solve for y in #6x-3y=9#?

Answer 1

Ethan Adkins

#y=2x-3#

As we have two variables #x# and #y# here

so we can solve for #y# only in terms of #x#.

As #6x-3y=9#, adding #3y-9# to both sides, we get

#6x-3y+3y-9=9+3y-9#

or #6x-cancel(3y)+cancel(3y)-9=cancel9+3y-cancel9#

or #6x-9=3y#

or #3y=6x-9# - now multipying both sides by #1/3#, we get

#1/3xx3y=1/3xx6x-1/3xx9#

or #y=2x-3#

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Answer 2

Ethan Adkins

To solve for ( y ) in ( 6x - 3y = 9 ), you first need to isolate ( y ) on one side of the equation. Start by subtracting ( 6x ) from both sides:

[ 6x - 6x - 3y = 9 - 6x ]

This simplifies to:

[ -3y = 9 - 6x ]

Then, divide both sides by ( -3 ) to solve for ( y ):

[ \frac{-3y}{-3} = \frac{9 - 6x}{-3} ]

[ y = \frac{-9 + 6x}{3} ]

This can be further simplified to:

[ y = -3 + 2x ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.