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How do you solve for y in #3x +4y=12#?

Answer 1

Hazel Anglin

#y=color(blue)((12-3x)/4#

#3x+color(green)(4y)=12#

To solve for #y# we would need to isolate the term containing #y# on the L.H.S

#4y=12-color(green)(3x#

#y=color(blue)((12-3x)/4#

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Answer 2

Avery Alexander

To solve for ( y ) in ( 3x + 4y = 12 ), you need to isolate ( y ) on one side of the equation. First, subtract ( 3x ) from both sides to move the ( 3x ) term to the right side of the equation. Then, divide both sides by ( 4 ) to isolate ( y ). The equation becomes ( y = \frac{12 - 3x}{4} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.