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How do you solve for y in #3(x-1)+2x=3x+y#?

Answer 1

Abigail Allen

#y=-3#

#3(x-1)+2x=3x+y# #rArr 3x -3=3x+y# #rArr y=3x-3x-3# #:. y=-3#

Hope this helps :)

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Answer 2

Jameson Allen

To solve for ( y ) in the equation ( 3(x-1)+2x=3x+y ), follow these steps:

Expand and simplify the left side of the equation: ( 3(x-1)+2x = 3x - 3 + 2x = 5x - 3 )
Subtract ( 3x ) from both sides of the equation: ( 5x - 3 - 3x = y ) ( 2x - 3 = y )

Therefore, ( y = 2x - 3 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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