How do you solve for y #-2= 7x -(-1)/16#?

Answer 1

Julia Adams

#y=\frac{112x+33}{16}#

Given that #y-2=7x-{-1}/16#

#y=7x+1/16+2#

#y={7x\cdot 16+1+2\cdot 16}/16#

#y=\frac{112x+33}{16}#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eva Adamson

To solve for ( y ) in the equation ( -2 = \frac{7x - (-1)}{16} ), you can follow these steps:

Start by simplifying the expression inside the parentheses: ( 7x - (-1) = 7x + 1 ).
Rewrite the equation with the simplified expression: ( -2 = \frac{7x + 1}{16} ).
Multiply both sides of the equation by 16 to eliminate the fraction: ( -2 \times 16 = 7x + 1 ).
Simplify the equation: ( -32 = 7x + 1 ).
Subtract 1 from both sides of the equation: ( -32 - 1 = 7x ).
Simplify: ( -33 = 7x ).
Divide both sides of the equation by 7 to solve for ( x ): ( \frac{-33}{7} = x ).
Simplify: ( x = -\frac{33}{7} ).

Therefore, the solution for ( x ) is ( x = -\frac{33}{7} ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.