# How do you solve for #x in RR# the equation #x! = e^x# ?

I got

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As Gamma grows faster then the exponential I would assume this is the only solution.

graph{(y-x!)(y-e^x)=0 [-10, 10, -50, 300]}

If I have time, I will share an asymptotic solution.

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To solve for x in the equation x! = e^x, we can use numerical methods or approximations. There is no algebraic or analytical solution for this equation. One common numerical method is to use iterative techniques such as Newton's method or the bisection method to find an approximate solution.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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