# How do you solve for x in #m^2x-3m^2=12m^2#?

There are a couple ways to do this; here is one:

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To solve for x in the equation (m^{2x} - 3m^2 = 12m^2), first, add (3m^2) to both sides of the equation to get (m^{2x} = 15m^2). Then, take the natural logarithm (ln) of both sides to eliminate the exponent, which gives (2x \ln(m) = \ln(15) + 2 \ln(m)). Finally, divide both sides by (2\ln(m)) to isolate (x), yielding (x = \frac{\ln(15) + 2 \ln(m)}{2 \ln(m)}).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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