# How do you solve for x in #L = Ax + (1 + B)x#?

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To solve for ( x ) in ( L = Ax + (1 + B)x ), you would factor out the common term ( x ), resulting in ( L = x(A + 1 + B) ). Then, divide both sides by ( A + 1 + B ) to isolate ( x ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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