How do you solve for x in #ax+b=cx+d #?

Answer 1

#x=(d-b)/(a-c), a-c!=0#

Separate the words using x:

#ax+b=cx+d#
#ax-cx=d-b#

Take x out of the equation:

#x(a-c)=d-b#

separate:

#x=(d-b)/(a-c), a-c!=0#
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Answer 2

To solve for ( x ) in the equation ( ax + b = cx + d ), you can follow these steps:

  1. Move the terms involving ( x ) to one side of the equation.
  2. Combine like terms.
  3. Solve for ( x ) by isolating it on one side of the equation.
  4. Once you have ( x ), you can substitute its value back into the original equation to verify the solution.
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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