How do you solve for x in #5ax-c=4c+ax #?
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To solve for ( x ) in the equation ( 5ax - c = 4c + ax ), first, gather all terms containing ( x ) on one side and constants on the other side. Then, combine like terms and isolate ( x ) by dividing both sides by the coefficient of ( x ). The solution is ( x = \frac{5c}{4a + 1} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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