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How do you solve for x in #48/125=(3x)/25#?

Answer 1

Nathan Axel

#x=16/5#

One way is to express the fraction on the right side with the equivalent denominator to the fraction on the left side.

#rArr(3x)/25xx5/5=(15x)/125#

We now have #48/125=(15x)/125#

Since the fractions are equal and have the same denominator, then their numerators must be equal.

#rArr15x=48#

#rArrx=48/15=16/5#

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Answer 2

Jameson Allen

To solve for ( x ), first multiply both sides of the equation by ( 25 ). This will eliminate the fraction on the right side of the equation.

[ 48 \div 125 = \frac{3x}{25} ]

[ 25 \times \frac{48}{125} = 3x ]

[ \frac{25 \times 48}{125} = 3x ]

[ \frac{1200}{125} = 3x ]

[ 9.6 = 3x ]

Then, divide both sides of the equation by ( 3 ) to isolate ( x ).

[ \frac{9.6}{3} = x ]

[ x = 3.2 ]

So, ( x = 3.2 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.