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How do you solve for x in #1/4x = 3y = 4#?

Answer 1

If the question is accurate:
#color(white)("XXX")x=16#

If the equation really is #1/4x=3y=4# the #(=3y)# is redundant in finding the value of #x# #color(white)("XXX")1/4x=4# after multiplying both sides by #4# #color(white)("XXX")x=16#

If the first equal sign was intended to be a plus (they are on the same key on my keyboard) #color(white)("XXX")1/4x+3y=4# subtracting #(3y)# from both sides: #color(white)("XXX")1/4x=4-3y# then multiplying both sides by #4# #color(white)("XXX")x=16-12y#

If the second equal sign was intended to be a plus #color(white)("XXX")1/4x=3y+4# multiplying both sides by #4# #color(white)("XXX")x=12y+16#

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Answer 2

Jameson Allen

To solve for x in the equation 1/4x = 3y = 4, you first need to isolate x. Start by subtracting 3y from both sides to get 1/4x = 4 - 3y. Then, multiply both sides by 4 to eliminate the fraction, yielding x = 16 - 12y.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.