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How do you solve for x: #7/12(x-3)=1/3x+4#?

Answer 1

Genesis Allen

#x=23#

Multiplying the given equation by #12#

#7(x-3)=12/3x+48#

#7(x-3)=4x+48#

since #7(x-3)=7x-21#

we get

#7x-21=4x+48#

Adding #21#

#7x=4x+69#

subtracting #4x#

#3x=69# so

#x=23#

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Answer 2

Eva Adamson

#x=23#

Let's get rid of the fractions so we can just have a plain vanilla linear equation. We can multiply all terms by #12#. We get

#7(x-3)=4x+48#

We can next distribute the #7# to both terms in the parenthesis to get

#7x-21=4x+48#

Next, we can add #21# to both sides to further isolate the #x# terms. We will get

#7x=4x+69#

Subtracting #4x# from both sides gives us

#3x=69#

Lastly, we can divide both sides by #3# to get

#x=23#

Hope this helps!

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Answer 3

Eva Abramson

To solve for ( x ):

Expand both sides of the equation.
Combine like terms.
Isolate the variable ( x ).
Solve for ( x ).

Here are the steps:

Multiply both sides of the equation by 12 to eliminate the denominators.
Distribute and simplify.
Combine like terms.
Isolate ( x ) on one side of the equation.
Solve for ( x ).

The solution is ( x = 24 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.