# How do you solve for P in #S=B+(1/2)Pl#?

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To solve for ( P ) in the equation ( S = B + \frac{1}{2}Pl ), you first isolate the term containing ( P ) by subtracting ( B ) from both sides:

( S - B = \frac{1}{2}Pl )

Then, multiply both sides by ( \frac{2}{l} ) to isolate ( P ):

( P = \frac{2(S - B)}{l} )

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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