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How do you solve for m in #10m-p = -n + p m#?

Answer 1

#color(green)(m=(p-n)/(10-p)#

Given #color(white)("XXX")10m-p=-n+p m#

We need to get all the terms involving #m# on one side and all other terms on the other side: #color(white)("XXX")10m-p*m =p-n#

Extract the factor of #m# from the terms on the left side #color(white)("XXX")m(10-p)=p-n#

(Assuming #p!=10#) divide both sides by #(10-p)# isolating a single #m# on the left side #color(white)("XXX")m=(p-n)/(10-p)#

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Answer 2

Ethan Adkins

To solve for ( m ) in the equation ( 10m - p = -n + p m ), you first need to isolate ( m ) on one side of the equation. Here's the solution step by step:

Add ( p ) to both sides of the equation to group the ( m ) terms: ( 10m - p + p = -n + pm + p ) This simplifies to: ( 10m = -n + pm + p )
Subtract ( pm ) from both sides of the equation to isolate the ( m ) term: ( 10m - pm = -n + p )
Factor out ( m ) from the left side of the equation: ( m(10 - p) = -n + p )
Finally, divide both sides by ( (10 - p) ) to solve for ( m ): ( m = \frac{-n + p}{10 - p} )

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.