How do you solve for each of the variable #50=2s + 5p#?

Answer 1

Subtract #5p# from both sides then divide both sides by #2# to get:

#s = 25 - (5p)/2#

Subtract #2s# from both sides then divide both sides by #5# to get:

#p = 10 - (2s)/5#

Subtract #5p# from both sides to get:
#50 - 5p = 2s#
Then divide both sides by #2# to get:
#color(red)(s = 25 - (5p)/2)#
Starting again, subtract #2s# from both sides to get:
#50 - 2s = 5p#
Then divide both sides by #5# to get:
#color(red)(p = 10 - (2s)/5)#
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Answer 2

To solve for each variable, isolate one variable at a time by performing the necessary operations.

Given the equation: 50 = 2s + 5p

To solve for s, subtract 5p from both sides: 50 - 5p = 2s

Then, divide both sides by 2: (50 - 5p) / 2 = s

To solve for p, subtract 2s from both sides: 50 - 2s = 5p

Then, divide both sides by 5: (50 - 2s) / 5 = p

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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