How do you solve for d in #n= (dh)/(f+d)#?

Answer 1

#color(green)((nf)/(h-n) = d)#

To solve for #d#, we need to get it by itself (isolate the variable). First, undo the division by multiplying both sides by the denominator.
#n = (dh)/(f+d)#
#(f+d)/1 * n/1 = (dh)/cancel(f+d) * cancel(f+d)/1#
#((f+d)timesn) = dh#
#nf + nd = dh#
Now get all terms with #d# to one side and factor out the #d#.
#nf = dh-nd#
#nf = d(h-n)#
Finish isolating the variable by getting #d# by itself.
#(nf)/(h-n) = (d(cancel(h-n)))/cancel(h-n)#
#color(green)((nf)/(h-n) = d)#

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Answer 2

To solve for ( d ) in the equation ( n = \frac{dh}{f + d} ), where ( n ), ( h ), ( f ), and ( d ) are variables:

  1. Start by multiplying both sides of the equation by ( f + d ).
  2. This gives you ( n(f + d) = dh ).
  3. Expand the left side of the equation by distributing ( n ) across ( f + d ), resulting in ( nf + nd = dh ).
  4. Move all terms involving ( d ) to one side of the equation and all other terms to the other side.
  5. This yields ( nd - dh = -nf ).
  6. Factor out ( d ) from the left side, resulting in ( d(n - h) = -nf ).
  7. Finally, divide both sides of the equation by ( n - h ) to isolate ( d ), giving you ( d = \frac{-nf}{n - h} ).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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