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How do you solve for c: #5c-4-2c+1=8c+2#?

Answer 1

Isaiah Anthony

#c=-1#

#5c-4-2c+1=8c+2#

Simplify, group, and then simplify once more.

#3c-3=8c+2#

#3c-8c=2+3#

#-5c=5#

Divide both sides by #5#.

#-c=1# or #c=-1#

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Answer 2

Kennedy Adams

To solve for ( c ) in the equation ( 5c - 4 - 2c + 1 = 8c + 2 ), you would first combine like terms on both sides of the equation. This yields ( 3c - 3 = 8c + 2 ). Then, you would isolate the variable ( c ) by moving all terms involving ( c ) to one side of the equation and the constant terms to the other side. This results in ( 3c - 8c = 2 + 3 ), which simplifies to ( -5c = 5 ). Finally, divide both sides by -5 to find the value of ( c ), giving ( c = -1 ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.