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How do you solve for A in #B=5/7(A-9)#?

Answer 1

See a solution process below:

First, multiply each side of the equation by #color(red)(7)/color(blue)(5)# to eliminate the need for parenthesis while keeping the equation balanced:

#color(red)(7)/color(blue)(5) xx B = color(red)(7)/color(blue)(5) xx 5/7(A - 9)#

#7/5B = cancel(color(red)(7))/cancel(color(blue)(5)) xx color(blue)(cancel(color(black)(5)))/color(red)(cancel(color(black)(7)))(A - 9)#

#7/5B = A - 9#

Now, add #color(red)(9)# to each side of the equation to solve for #A# while keeping the equation balanced:

#7/5B + color(red)(9) = A - 9 + color(red)(9)#

#7/5B + 9 = A - 0#

#7/5B + 9 = A#

#A = 7/5B + 9#

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Answer 2

Hazel Anglin

To solve for A, you first isolate A by multiplying both sides of the equation by the reciprocal of 5/7, which is 7/5. Then, simplify the equation to find the value of A. So, the solution is A = (7/5) * B + 9.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.