How do you solve #e^ { y } = 6#?

Answer 1

#y=1.79#(2dps)#

#e^y=6#

take natural logs of both sides

#lne^y=ln6#
#=>y=ln6#
#y~~1.791759469....#
#y=1.79#(2dps)#
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Answer 2

To solve ( e^y = 6 ), you can take the natural logarithm (ln) of both sides of the equation. This gives:

[ \ln(e^y) = \ln(6) ]

Using the property of logarithms that states ( \ln(e^x) = x ), the left side simplifies to just ( y ):

[ y = \ln(6) ]

So, the solution to the equation is ( y = \ln(6) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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