# How do you solve #e^ { y } = 6#?

take natural logs of both sides

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To solve ( e^y = 6 ), you can take the natural logarithm (ln) of both sides of the equation. This gives:

[ \ln(e^y) = \ln(6) ]

Using the property of logarithms that states ( \ln(e^x) = x ), the left side simplifies to just ( y ):

[ y = \ln(6) ]

So, the solution to the equation is ( y = \ln(6) ).

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