How do you solve #e^(x+1) = 30#?

Answer 1

#x=ln(30)-1approx2.4012#

In order to undo the exponentiation, take the natural logarithm of both sides. (The natural logarithm, denoted #ln#, is equivalent to #log_e#.) Since logarithms are the inverse of exponential functions, taking the logarithm will isolate the #x# term.
#e^(x+1)=30#
#ln(e^(x+1))=ln(30)#
#x+1=ln(30)#
#x=ln(30)-1approx2.4012#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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