How do you solve compound inequalities # 11< 3y +2 < 20#?
Inequalities are maintained if you
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To solve the compound inequality 11 < 3y + 2 < 20, first subtract 2 from each part of the inequality to isolate 3y in the middle: 11 - 2 < 3y < 20 - 2, which simplifies to 9 < 3y < 18. Then, divide each part by 3 to solve for y: 9/3 < y < 18/3, which further simplifies to 3 < y < 6. Therefore, the solution to the compound inequality is 3 < y < 6.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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