How do you solve by substitution # x + y = 10# and #y = x + 8#?

Answer 1

Savannah Anderson

#color(magenta)(therefore x=1 and y=9#

#y=x+8#

Considering that,

#x+y=10#

#x+x+8=10#

#2x+10=8#

#2x=10-8#

#2x=2#

#x=2/2#

#color(red)(x=1#

#y=x+8#

#y=1+8#

#color(red)(y=9#

#color(magenta)(therefore x=1 and y=9#

I hope this is helpful.

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Answer 2

Eva Adamson

To solve by substitution for the system of equations (x + y = 10) and (y = x + 8), you substitute the expression for (y) from the second equation into the first equation.

Substituting (x + 8) for (y) in the first equation gives:

[x + (x + 8) = 10]

Then, solve for (x):

[2x + 8 = 10] [2x = 10 - 8] [2x = 2] [x = 1]

After finding (x = 1), substitute this value back into either of the original equations to solve for (y).

Using the second equation (y = x + 8):

[y = 1 + 8] [y = 9]

Therefore, the solution is (x = 1) and (y = 9).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.