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How do you solve by completing the square #x^2+6x+2=0#?

Answer 1

Julia Adams

The response is

#x^2+6x+9-9+2=0rArr(x+3)^2=7rArr#

#x+3=+-sqrt7rArrx=-3+-sqrt7#.

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Answer 2

Kennedy Adams

To solve the quadratic equation x^2 + 6x + 2 = 0 by completing the square, follow these steps:

Move the constant term to the other side: x^2 + 6x = -2
To complete the square, take half of the coefficient of x, square it, and add it to both sides: x^2 + 6x + (6/2)^2 = -2 + (6/2)^2 x^2 + 6x + 9 = -2 + 9 x^2 + 6x + 9 = 7
Rewrite the left side as a perfect square trinomial: (x + 3)^2 = 7
Take the square root of both sides and solve for x: x + 3 = ±√7 x = -3 ± √7

Therefore, the solutions to the equation x^2 + 6x + 2 = 0 by completing the square are x = -3 + √7 and x = -3 - √7.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.