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How do you solve #(b+2)/3 - (b-2)/7=2#?

Answer 1

Avery Alexander

Solution: #b=5 1/2#

#(b+2)/3- (b-2)/7=2# . Multiplying by #21# on both sides

we get, #7(b+2)- 3(b-2)=42# or

#7 b+14- 3 b +6=42# or

#4 b=22 :. b= 22/4= 11/2 = 5 1/2#

Solution: #b=5 1/2# [Ans]

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Answer 2

Hazel Anglin

To solve the equation (b+2)/3 - (b-2)/7 = 2, you can follow these steps:

Multiply both sides of the equation by the least common denominator (LCD) of 3 and 7, which is 21, to eliminate the denominators.
Simplify the equation by distributing the LCD to each term.
Combine like terms on both sides of the equation.
Isolate the variable term, b, on one side of the equation by moving the constant terms to the other side.
Simplify the equation further by performing any necessary arithmetic operations.
Solve for b by dividing both sides of the equation by the coefficient of b.
Check the solution by substituting the value of b back into the original equation to ensure it satisfies the equation.

The solution to the equation (b+2)/3 - (b-2)/7 = 2 is b = 10.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.