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How do you solve and write the following in interval notation: #x+3+12x< -3+5x+48#?

Answer 1

Solution set with interval notation # x: (- oo ,21/4) #

#x+3+12x< -3+5x+48 or 13x+3<5x+45 or 13x-5x < 42 or 8x<42 or 4x<21 or x <21/4 # Solution set with interval notation # x: (- oo ,21/4) #[Ans]

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Answer 2

Avery Alexander

To solve the inequality (x + 3 + 12x < -3 + 5x + 48), first combine like terms on both sides of the inequality to simplify the expression. Then, isolate the variable (x). Finally, express the solution in interval notation.

(x + 3 + 12x < -3 + 5x + 48)

(13x + 3 < 5x + 45)

(13x - 5x < 45 - 3)

(8x < 42)

(x < \frac{42}{8})

(x < \frac{21}{4})

So, the solution in interval notation is ((-∞, \frac{21}{4})).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve and write the following in interval notation: #x+3+12x&lt; -3+5x+48#?

How do you solve and write the following in interval notation: #x+3+12x< -3+5x+48#?