How do you solve and write the following in interval notation: #abs(2x+9) ≤ 3#?
The solution is
This equation has two solutions.
We must find a solution to
Consequently, the answers are
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To solve the inequality ( 2x+9 \leq 3 ) and write the solution in interval notation, follow these steps:
 Set up two inequalities: ( 2x+9 \leq 3 ) and ( (2x+9) \leq 3 ).
 Solve each inequality separately for ( x ).
 Write the solutions in interval notation.
Solutions:

For ( 2x+9 \leq 3 ): ( 2x \leq 6 ) ( x \leq 3 )

For ( (2x+9) \leq 3 ): ( 2x  9 \leq 3 ) ( 2x \leq 12 ) ( x \geq 6 )
Combine the solutions: [ x \in [3, 6] ]
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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