How do you solve and write the following in interval notation: # | 5x + 3 | >18#?

Answer 1
When you have the absolute value, you can remove it considering the two sign #\pm#. You have to be careful with the inequality because the #+# keep the direction of the inequality while the #-# inverte it. In your case you have
#|5x+3|>18#
#5x+3>18# and #5x+3<-18#
#5x>15# and #5x<-21#
#x>3# and #x<-21/5#.
As interval you can say that #x in (-oo, -21/5) and (3, +oo)#.
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Answer 2

To solve the inequality ( |5x + 3| > 18 ), you can follow these steps:

  1. Split the absolute value inequality into two separate inequalities: ( 5x + 3 > 18 ) and ( 5x + 3 < -18 )

  2. Solve each inequality individually: ( 5x + 3 > 18 ) Subtract 3 from both sides: ( 5x > 15 ) Divide by 5: ( x > 3 )

    ( 5x + 3 < -18 ) Subtract 3 from both sides: ( 5x < -21 ) Divide by 5: ( x < -\frac{21}{5} )

  3. Write the solutions in interval notation: For ( x > 3 ), the interval notation is ( (3, \infty) ) For ( x < -\frac{21}{5} ), the interval notation is ( (-\infty, -\frac{21}{5}) )

So, the solution to ( |5x + 3| > 18 ) in interval notation is ( (-\infty, -\frac{21}{5}) \cup (3, \infty) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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