How do you solve and write the following in interval notation: #-4<a + 2<10#?

Answer 1

#a in ]-6,8[#

you can subtract 2 to all terms:

#-6< a<8#
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Answer 2

#-6 < a < 8#; #(-6,8)#

Subtract two.

#-4 < a + 2 < 10#
#-4 -2 < a + 2 -2<10-2#
#-6 < a < 8#

Interval Notation:

#(-6,8)#

Parenthesis do not include values, and brackets include the values they cover in interval notation.

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Answer 3

To solve and write the inequality -4 < a + 2 < 10 in interval notation, first subtract 2 from each part: -4 - 2 < a < 10 - 2, which simplifies to -6 < a < 8. Then, write the solution in interval notation: (-6, 8).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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