# How do you solve and write the following in interval notation: # 3x – 2 <7# and #–3x <= 15#?

Se a solution process below:

Solve First Equation For x:

Solve second Equation For x:

The Solution Is:

Or, in interval notation:

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To solve the system of inequalities 3x - 2 < 7 and -3x ≤ 15, you first solve each inequality separately.

For the first inequality, 3x - 2 < 7, you add 2 to both sides, resulting in 3x < 9. Then, divide both sides by 3, giving x < 3.

For the second inequality, -3x ≤ 15, you divide both sides by -3, remembering to reverse the inequality sign when dividing by a negative number. This yields x ≥ -5.

In interval notation, the solution to the system of inequalities is (-∞, 3) for x < 3 and [-5, ∞) for x ≥ -5.

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