How do you solve and write the following in interval notation: #2x + 9 >= 15#?
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To solve the absolute value inequality 2x + 9 ≥ 15 and write the solution in interval notation:

First, isolate the absolute value expression by considering two cases: when the expression inside the absolute value is positive and when it is negative.

For the case when 2x + 9 is positive: 2x + 9 ≥ 15 Solve for x: x ≥ 3

For the case when 2x + 9 is negative: (2x + 9) ≥ 15 Solve for x: x ≤ 12

Combine the solutions from both cases: x ≤ 12 or x ≥ 3

Write the solution in interval notation: (∞, 12] ∪ [3, ∞)
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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