How do you solve and write the following in interval notation: #|2x + 9 |>= 15#?
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To solve the absolute value inequality |2x + 9| ≥ 15 and write the solution in interval notation:
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First, isolate the absolute value expression by considering two cases: when the expression inside the absolute value is positive and when it is negative.
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For the case when 2x + 9 is positive: 2x + 9 ≥ 15 Solve for x: x ≥ 3
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For the case when 2x + 9 is negative: -(2x + 9) ≥ 15 Solve for x: x ≤ -12
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Combine the solutions from both cases: x ≤ -12 or x ≥ 3
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Write the solution in interval notation: (-∞, -12] ∪ [3, ∞)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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