How do you solve and graph #p-6=3#?

Question

How do you solve and graph #p-6>=3#?

Nathan Axel · Accepted Answer

See explanatom

Treat the manipulation the same way you would a normal equation.

Add 6 to both sides

#color(green)(p-6color(red)(+6)" ">=" "3color(red)(+6))#

But -6+6=0

#p+0" ">= 9#

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I know that they use the variable p but you would plot this the same way as you would #y>=9#

So the graph represents the equivalent of all the values of #y# that are greater than or equal to 9 no matter what value of #x#

As the 'p' may take on the value of 9 you use a solid line.

Just for a moment, suppose #p# could not take on the value of 9 #(p>9)# then the line would need to be dotted to indicate this condition

Julia Adams · Answer

undefined To solve and graph the inequality $ p - 6 \geq 3 $, follow these steps:

1. Add 6 to both sides of the inequality to isolate the variable $ p $:
$$ p - 6 + 6 \geq 3 + 6 $$
$$ p \geq 9 $$

2. Plot a closed circle on the number line at $ p = 9 $ to represent the solution because the inequality includes equality ($ \geq $).
3. Shade the region to the right of the closed circle, indicating all values of $ p $ greater than or equal to 9.

Graphically, this represents all values of $ p $ greater than or equal to 9.

How do you solve and graph #p-6&gt;=3#?

How do you solve and graph #p-6>=3#?