How do you solve and graph #abs(n+5)>=3#?
(the reds)
Graph: On n axis: -------------0------------->n
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To solve the absolute value inequality ( |n + 5| \geq 3 ), you'll need to consider two cases:
- ( n + 5 \geq 3 )
- ( -(n + 5) \geq 3 )
Solve each case separately to find the values of ( n ). Then, graph the solution on a number line.
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For the first case, ( n + 5 \geq 3 ), subtract 5 from both sides to get ( n \geq -2 ).
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For the second case, ( -(n + 5) \geq 3 ), distribute the negative sign and solve for ( n ), which gives ( -n - 5 \geq 3 ). Add 5 to both sides and then multiply both sides by -1 (to reverse the inequality when multiplying by a negative number), yielding ( n \leq -8 ).
Thus, the solution is ( n \leq -8 ) or ( n \geq -2 ). On the number line, graph a closed circle at -8 and -2, then shade to the left of -8 and to the right of -2.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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