How do you solve and graph #abs(n+5)>=3#?
(the reds)
Graph: On n axis: 0>n
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To solve the absolute value inequality ( n + 5 \geq 3 ), you'll need to consider two cases:
 ( n + 5 \geq 3 )
 ( (n + 5) \geq 3 )
Solve each case separately to find the values of ( n ). Then, graph the solution on a number line.

For the first case, ( n + 5 \geq 3 ), subtract 5 from both sides to get ( n \geq 2 ).

For the second case, ( (n + 5) \geq 3 ), distribute the negative sign and solve for ( n ), which gives ( n  5 \geq 3 ). Add 5 to both sides and then multiply both sides by 1 (to reverse the inequality when multiplying by a negative number), yielding ( n \leq 8 ).
Thus, the solution is ( n \leq 8 ) or ( n \geq 2 ). On the number line, graph a closed circle at 8 and 2, then shade to the left of 8 and to the right of 2.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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