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How do you solve and graph #abs(c+2)> -2#?

Answer 1

Julia Adams

The solution is #c in RR#

This is an inequality with absolute values.

#|c+2| > -2#

#AA c in RR#

#|c+2|# is always greater than #-2#

graph{(y-|x+2|)(y+2)=0 [-10, 10, -5, 5]}

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Answer 2

Jace Anderson

To solve and graph the inequality |c + 2| > -2, you first recognize that the absolute value of any real number is always non-negative. Thus, the absolute value of c + 2 will always be greater than or equal to 0. Therefore, the inequality |c + 2| > -2 is true for all real numbers. As such, the solution set includes all real numbers. To graph this, you would draw a number line with an arrow extending in both directions to indicate that the solution set includes all real numbers.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve and graph #abs(c+2)&gt; -2#?

How do you solve and graph #abs(c+2)> -2#?