# How do you solve and graph #a/9>=-15#?

See a solution process below:

chart{x >= -135 [-150, 150, -75, 75]}

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To solve the inequality ( \frac{a}{9} \geq -15 ), you would first multiply both sides by 9 to isolate the variable ( a ). This gives you ( a \geq -15 \times 9 ), which simplifies to ( a \geq -135 ).

To graph this solution on a number line, you would draw a closed circle at -135 (since it includes -135), and shade to the right, indicating that ( a ) can be any value greater than or equal to -135.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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