How do you solve and graph #8r+6<9r#?
See a solution process below:
8r + 6 < -color(red)(8r) + 9r#-color(red)(8r) + 8r
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graph{x>6 [-16.02, 16.01, -8.01, 8.01]}
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To solve and graph the inequality (8r + 6 < 9r), first, subtract (8r) from both sides to isolate (r) on one side of the inequality. Then, subtract 6 from both sides. Finally, graph the solution on a number line.
[ \begin{align*} 8r + 6 &< 9r \ 6 &< 9r - 8r \ 6 &< r \end{align*} ]
On a number line, draw an open circle at 6 (because the inequality is less than, not less than or equal to), then shade to the right since (r) is greater than 6.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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