How do you solve and graph #5-2x>=27#?
See a solution process below:
The line will be a solid line because the inequality operator contains an "or equal to" clause.
We will shade to the left side of the line because the inequality operator also contains a "less than" clause:
graph{x <= -11 [-20, 20, -10, 10]}
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To solve the inequality 5 - 2x ≥ 27, you first subtract 5 from both sides to isolate the term with x. This gives you -2x ≥ 22. Then, divide both sides by -2. Since you're dividing by a negative number, you need to flip the inequality sign. So, x ≤ -11.
To graph this inequality on a number line, you would draw a closed circle at -11 (since it includes -11) and shade everything to the left of -11 to represent all the values of x that satisfy the inequality.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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