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How do you solve and graph #3x + 2 ≤ 1#?

Answer 1

#x<=-1/3#

#3x+2<=1#

#3x<=-1#

#x<=-1/3#

graph will be a vertical line at #x=-1/3# and you shade the area to the left where #x# is less than #-1/3#, the line will be solid since #x# also is equal to #-1/3#

graph{x<=-1/3 [-10, 10, -5, 5]} #

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Answer 2

Isaiah Anthony

To solve the inequality 3x + 2 ≤ 1, you first isolate x by subtracting 2 from both sides, yielding 3x ≤ -1. Then, divide both sides by 3 to find x ≤ -1/3. To graph this solution on a number line, plot a closed circle at -1/3 and shade to the left to indicate all values less than or equal to -1/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.