How do you solve and graph #2a<=-4+a#?

Answer 1

Isaiah Anthony

#a<=-4#

#2a <= -4 + a#
Subtract #color(red)(a)# from both sides
#2a - color(red)a<=-4 + cancela - cancelcolor(red)a#
#a <= 4#

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Answer 2

Hazel Anglin

To solve and graph the inequality (2a \leq -4 + a), follow these steps:

Subtract (a) from both sides: [2a - a \leq -4] [a \leq -4]
Now, you have the solution for (a). To graph the inequality on a number line:
- Draw a solid dot at -4 to represent the inclusive endpoint.
- Shade the region to the left of -4, indicating all values of (a) less than or equal to -4.
Label the shaded region to indicate that it represents the solution to the inequality.

So, the solution and graph for the inequality (2a \leq -4 + a) are: (a \leq -4), and the shaded region on the number line extends to the left from -4, including -4 itself.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you solve and graph #2a&lt;=-4+a#?

How do you solve and graph #2a<=-4+a#?