How do you solve and check your solutions to #c/5.3+8.3=11.3#?

Answer 1

See the entire solution and validation process below:

To solve this problem, first subtract #color(red)(8.3)# from each side of the equation to isolate the #c# term while keeping the equation balanced:
#c/5.3 + 8.3 - color(red)(8.3) = 11.3 - color(red)(8.3)#
#c/5.3 + 0 = 3#
#c/5.3 = 3#
Now, multiply each side of the equation by #color(red)(5.3)# to solve for #c# while keeping the equation balanced:
#c/5.3 xx color(red)(5.3) = 3 xx color(red)(5.3)#
#c/color(red)(cancel(color(black)(5.3))) xx cancel(color(red)(5.3)) = 15.9#
#c = 15.9#
To validate this solution, substitute #15.9# for #c# in the original equation and ensure the left side of the equation calculates out to #11.3#
#15.9/5.3 + 8.3 = 11.3#
#3 + 8.3 = 11.3#
#11.3 = 11.3#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

To solve the equation ( \frac{c}{5.3} + 8.3 = 11.3 ), you first isolate the variable ( c ) by subtracting 8.3 from both sides of the equation:

[ \frac{c}{5.3} = 11.3 - 8.3 ]

[ \frac{c}{5.3} = 3 ]

Then, multiply both sides of the equation by 5.3 to solve for ( c ):

[ c = 3 \times 5.3 ]

[ c = 15.9 ]

To check the solution, substitute ( c = 15.9 ) into the original equation:

[ \frac{15.9}{5.3} + 8.3 = 11.3 ]

[ 3 + 8.3 = 11.3 ]

[ 11.3 = 11.3 ]

Since both sides of the equation are equal, the solution is correct.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7