How do you solve and check your solutions to #7=t/-7#?

Answer 1

See a solution process below:

Multiply each side of the equation by #color(red)(-7)# to solve for #t# while keeping the equation balanced:
#color(red)(-7) xx 7 = color(red)(-7) xx t/-7#
#-49 = cancel(color(red)(-7)) xx t/color(red)(cancel(color(black)(-7)))#
#-49 = t#
#t = -49#
To check the solution we need to substitute #-49# for #t# in the original equation and calculate the right side of the equation:
#7 = t/-7# becomes:
#7 = (-49)/-7#

Seven is 7.

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Answer 2

#t=-49#

Your equation can be put in the following order (by multiplying both sides by -7):

# 7times(-7) = (t/-7)times-7#

after which you could write:

#-49 = t#

That's your response.

#t = -49#

The result of dividing t by -7 is

#-49/-7#

You obtain

#=(-7times7)/-7 = 7# which is equal to the first term (7) in your original equation.

It explains everything, I suppose.

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Answer 3

To solve the equation (7 = \frac{t}{-7}), first, multiply both sides of the equation by (-7) to isolate (t). You get (t = -7 \times 7 = -49). To check the solution, substitute (t = -49) back into the original equation: (7 = \frac{-49}{-7}). Simplify this to (7 = 7), which confirms that (t = -49) is the correct solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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