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How do you solve and check your solution given #y+1 1/3=3 1/18#?

Answer 1

Hazel Anglin

You first want to get #y# to one side, and the numbers to the other.

Subtract #1 1/3# from both sides:

#y+cancel(1 1/3)-cancel(1 1/3)=3 1/18-1 1/3#

To work this, we have to multiply the #1/3# by 1 disguised as #6/6#:

#y=3+1/18-1-(1/3xx6/6)#

#y=3-1+1/18-6/18=2-5/18#; we split the #2#

#y=(1+18/18)-5/18=1+13/18=1 13/18#

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Answer 2

Kennedy Adams

To solve the equation (y + \frac{1}{3} = 3\frac{1}{18}), first subtract (\frac{1}{3}) from both sides to isolate (y). Then, convert (3\frac{1}{18}) to an improper fraction, which equals (\frac{55}{18}). Next, subtract (1) from (3\frac{55}{18}) to get (\frac{37}{18}). So, (y = \frac{37}{18}). To check the solution, plug (\frac{37}{18}) into the original equation for (y) and verify that the equation holds true.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.