How do you solve absolute value inequality #-3abs(2x-5)<9#?

Answer 1
Normally we would consider the two cases #(2x-5)# is negative and #(2x-5)# is positive or zero, separately and evaluate each case for restrictions on the value of #x#.
However, in this case #(-3)abs(2x-5)<9# can be re-written as #abs(2x-5)> -3# (by dividing both sides by #(-3)# and reversing the inequality)
#abs(2x-5) >=0 >-3# for all values of #x# (based on the definition of absolute value
so the solution to the given inequality is #x epsilon (-oo,+oo)#
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Answer 2

To solve the absolute value inequality -3|2x - 5| < 9, you would first isolate the absolute value term, then divide both sides by the coefficient of the absolute value. Finally, you would solve the resulting inequality.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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