# How do you solve #abs(y+3)+4=20#?

These values are the solutions if you substitute them into the left side of the equation and see if they equal the right side.

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To solve the equation abs(y+3) + 4 = 20, first isolate the absolute value term:

abs(y+3) = 20 - 4 abs(y+3) = 16

Now, split the equation into two cases based on the possible values of (y+3):

Case 1: y+3 is positive or zero: For this case, abs(y+3) = y+3. So, we have: y + 3 = 16

Case 2: y+3 is negative: For this case, abs(y+3) = -(y+3). So, we have: -(y + 3) = 16

Now, solve each case separately:

Case 1: y + 3 = 16 y = 16 - 3 y = 13

Case 2: -(y + 3) = 16 -y - 3 = 16 -y = 16 + 3 -y = 19 Multiply both sides by -1 to solve for y: y = -19

So, the solutions are y = 13 and y = -19.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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