How do you solve #abs(-x-9)=1#?

Answer 1

See the entire solution process below:

Because this equation contains an absolute value function it is a special case. The absolute value function takes any negative or positive term and transforms it into it's positive form. Therefore, there are two solutions to this problem. To solve you must take the term within the absolute value and solve for both the negative and positive form of what it is equated to.

Solution 1)

#-x - 9 = -1#
#-x - 9 + color(red)(9) = -1 + color(red)(9)#
#-x - 0 = 8#
#-x = 8#
#color(red)(-1) xx -x = #color(red)(-1) xx 8#
#x = -8#

Solution 2)

#-x - 9 = 1#
#-x - 9 + color(red)(9) = 1 + color(red)(9)#
#-x - 0 = 10#
#-x = 10#
#color(red)(-1) xx -x = #color(red)(-1) xx 10#
#x = -10#

The solution to this problem is:

#x = -8# and #x = -10#
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Answer 2

To solve the equation (|\text{-}x-9|=1), you would consider two cases:

  1. (\text{-}x-9 = 1), which simplifies to (x = -10).
  2. (\text{-}x-9 = \text{-}1), which simplifies to (x = -8).

Therefore, the solutions are (x = -10) and (x = -8).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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