How do you solve #abs(x+3) = 5#?
Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
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To solve the equation |x + 3| = 5, you need to consider two cases: when the expression inside the absolute value is positive and when it is negative.
Case 1: x + 3 is positive: x + 3 = 5 x = 5 - 3 x = 2
Case 2: x + 3 is negative: -(x + 3) = 5 -x - 3 = 5 -x = 5 + 3 -x = 8 x = -8
So, the solutions to the equation |x + 3| = 5 are x = 2 and x = -8.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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