How do you solve #abs(x+2)-5>=8#?
Solution:
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To solve abs(x+2) - 5 ≥ 8, first, isolate the absolute value term by adding 5 to both sides, then solve for x. This gives you abs(x+2) ≥ 13. To solve for x, consider both cases: when (x+2) is positive or zero, and when (x+2) is negative. Then solve each case separately.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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