How do you solve #-abs(d+2)=7#?

Answer 1

No solution

There is no solution, #abs(d+2)# is always positive due to the modulus, therefore #-abs(d+2)# is always negative and then cannot equal 7 leaving no possible solution.
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Answer 2

To solve -|d + 2| = 7, you first isolate the absolute value term by dividing both sides by -1. This gives you |d + 2| = -7. Since absolute values cannot be negative, there is no solution to this equation.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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