How do you solve #abs(7x+5)<23#?
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To solve the inequality |7x + 5| < 23, you first isolate the absolute value expression by considering two cases: when the expression inside the absolute value is positive and when it is negative.
Case 1: (7x + 5) is positive: 7x + 5 < 23
Case 2: (7x + 5) is negative: -(7x + 5) < 23
Solve each case separately to find the possible values of x. Then, combine the solutions.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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