How do you solve #abs(7x+5)<23#?

Answer 1

#x in (-4, 18/7)#

By the property: #|a| < b ==> -b < a < b# #-23 < 7x + 5 < 23#
#-23 - 5 < 7x < 23 - 5#
#-28/7 < x < 18/7#
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Answer 2

To solve the inequality |7x + 5| < 23, you first isolate the absolute value expression by considering two cases: when the expression inside the absolute value is positive and when it is negative.

Case 1: (7x + 5) is positive: 7x + 5 < 23

Case 2: (7x + 5) is negative: -(7x + 5) < 23

Solve each case separately to find the possible values of x. Then, combine the solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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