How do you solve #abs(7x + 2)= 10#?
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To solve the equation abs(7x + 2) = 10, you can split it into two cases:
- ( 7x + 2 = 10 ) when ( 7x + 2 ) is positive.
- ( -(7x + 2) = 10 ) when ( 7x + 2 ) is negative.
Solving for x in the first case: [ 7x + 2 = 10 ] [ 7x = 8 ] [ x = \frac{8}{7} ]
Solving for x in the second case: [ -(7x + 2) = 10 ] [ -7x - 2 = 10 ] [ -7x = 12 ] [ x = -\frac{12}{7} ]
So, the solutions are ( x = \frac{8}{7} ) and ( x = -\frac{12}{7} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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